The dual numbers: Ext-finite but not Ext-bounded #
Let k be a field, let A = k[ε] be the dual numbers k[ε]/(ε²), and let S = A/(ε) be the
residue field of A, viewed as an A-module. Every Ext group of the pair (S, S) is a
one-dimensional k-vector space (TauCeti.extDualNumberResidueEquiv), so TauCeti.IsExtFinite
holds while none of the groups vanishes and TauCeti.IsExtBounded fails: the alternating sum
∑ n, (-1)ⁿ dim_k Extⁿ(S, S) is not a finite sum. This is the example that separates the two
halves of TauCeti.IsEulerAdmissible. Since TauCeti.extEuler takes a proof of
TauCeti.IsEulerAdmissible as an argument, it cannot be instantiated for this pair and exposes no
totalised fallback value.
Main results #
TauCeti.not_isExtBounded_dualNumberResidue: no degree bounds theExt-support of(S, S). This half needs only a nontrivial commutative ring of coefficients.TauCeti.isExtFinite_dualNumberResidue: everyExtⁿ(S, S)is a finite-dimensionalk-vector space.TauCeti.not_isEulerAdmissible_dualNumberResidue: the pair(S, S)is not Euler-admissible.
References #
- Charles A. Weibel, An Introduction to Homological Algebra, Cambridge Studies in Advanced Mathematics 38, Cambridge University Press (1994), Section 2.5 and Chapter 4.
No degree is a vanishing bound for the Ext groups of k[ε]/(ε) against itself, because
none of them vanishes.
The dual-numbers rejection. Extⁿ(S, S) never vanishes, so the pair (S, S) is not
Ext-bounded.
Every Ext group of k[ε]/(ε) against itself is a finite-dimensional k-vector space.
The dual-numbers rejection. The residue field S of k[ε] is not Euler-admissible
against itself: its Ext groups are all one-dimensional, so Ext-finiteness holds
(TauCeti.isExtFinite_dualNumberResidue), but none of them vanishes, so the alternating sum
∑ n, (-1)ⁿ dim_k Extⁿ(S, S) is not a finite sum. Because TauCeti.extEuler consumes a proof of
TauCeti.IsEulerAdmissible, it cannot be instantiated for this pair and exposes no totalised
fallback value.